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JEE Advanced
Exam
JEE Advanced
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

JEE Advanced · Chemistry · Carboxylic Acid Derivatives

An aromatic tetracarboxylic acid (C_ 10 H_6 O_6) can form two type...

An aromatic tetracarboxylic acid (C10H6O6)\left(\mathrm{C}_{10} \mathrm{H}_6 \mathrm{O}_6\right) can form two type of monoanhydrides on heating with P2O5\mathrm{P}_2 \mathrm{O}_5 - The sum of locants of all carboxylic groups in this compound will be :An aromatic tetracarboxylic acid (C_ 10 H_6 O_6) can form two type of monoanhydrides on heating with P_2 O_5 - The sum

Correct answer

10

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An aromatic tetracarboxylic acid (C_ 10 H_6 O_6) can form two type of monoanhydrides on heating with P_2 O_5 - The sum
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