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Most Important Selected Qs for JEE AdvancedChemistryChemical Bonding and Molecular Structure

The number of equivalent contributing structures possible for XeO ₆⁴⁻ is m . The bond order of Xe - O bond is n . Find (m n) 0.2 . Round off your answer to the nearest integer.

Correct answer

4

Step-by-step solution

Bond order of XeO ₆⁴⁻ is 4 / 3=n It has 15 possible structures m=15 Thus mn =15 4 3 =20 0.2 mn =0.2 20=4

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