JEE Main2013Chemistryp Block Elements (Group 15, 16, 17 & 18)Actual

Oxidation state of sulphur in anions SO ₃²⁻, S ₂ O ₄²⁻ and S ₂ O ₆²⁻ increases in the orders :

Options

AS ₂ O ₆²⁻ < S ₂ O ₄²⁻ < SO ₃²⁻
BSO ₆²⁻ < S ₂ O ₄²⁻ < S ₂ O ₆²⁻
CS ₂ O ₄²⁻ < SO ₃²⁻ < S ₂ O ₆²⁻
DS ₂ O ₄²⁻ < S ₂ O ₆²⁻ < SO ₃²⁻

Correct answer

C. S ₂ O ₄²⁻ < SO ₃²⁻ < S ₂ O ₆²⁻

Step-by-step solution

In SO ₃⁻⁻ aligned & x+3(-2)=-2 ; x=+4 & In S ₂ O ₄⁻⁻ & 2 x+4(-2)=-2 & 2 x-8=-2 & 2 x=6 ; x=+3 & In S ₂ O ₆²⁻ & 2 x+6(-2)=-2 & 2 x=10 ; x=+5 aligned hence the correct order is S ₂ O ₄ ⁻⁻ < SO ₃⁻⁻ < S ₂ O ₆ ⁻⁻

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