Most Important Selected Qs for JEE AdvancedChemistryStates of Matter
A flask containing same He gas at 1.5 ~atm & 300 ~K is connected to another flask, four times larger in volume containing N ₂ at same temperature and pressure by means of narrow negligible volume tube. The bigger flask was then kept in a thermostat both maintained at 500 K , while other still at 300 K . Find final pressure. (mark the answer in atm)
Correct answer
2.2
Step-by-step solution
aligned & n ₁= x moles n ₂=4 x moles & V₁ n ₁ T₁ = V₂ n₂ T₂ aligned V n₁ 300 = 4 V n₂ 500 ...(i) And n ₂+ n ₁= x +4 x =5 x ...(ii) From (i) & (ii) n₁= 25 x 17 Then P₁ P₂ = n₁ n₂ in flask 1. 1.5 P = x n₁ P=2.2 ~atm