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Most Important Selected Qs for JEE AdvancedChemistryThermodynamics (C)

The ratio K p to K c of a reaction is 24.63 L atm mol –1 at 27°C. If heat of reaction at constant pressure is 98.8 kcal, what is the heat of reaction (in kcal) at constant volume?

Correct answer

98.20

Step-by-step solution

K p K c = RT Δn g RT Δn g = 24.63 L atm mol - 1 0.0821 × 3 0 0 Δ n g = 24.63 ∴ Δ n g = 1 Δ H = Δ E + Δ n g RT ∴ Δ E = Δ H - RT = 98.8 - 2 × 1 0 - 3 × 3 0 0 = 98.2 kcal

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