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JEE Advanced
Exam
JEE Advanced
Subject
Chemistry
Chapter
States of Matter

JEE Advanced · Chemistry · States of Matter

Paragraph According to Maxwell distribution law, the probability...

Paragraph According to Maxwell distribution law, the probability distribution function is given as below: F(v)=4π(M2πRT)3/2v2\mathrme−Mv2/2R T\mathbf{F}(\mathrm{v})=4 \pi\left(\frac{\mathrm{M}}{2 \pi \mathbf{R T}}\right)^{3 / 2} \mathrm{v}^2 \mathrme^{-M \mathrm{v}^2 / 2 R \mathrm{~T}} M-molar mass of gas, v-speed, R-gas constant, T-Absolute temperature Fraction of molecule in the range of v1v_1 to v2=∫v1v2f(v)dvv_2=\int_{v_1}^{v_2} f(v) d vQuestion Select the incorrect statement about a gas following Maxwell distribution law.

Options

  1. AExponential term implies that the fraction of molecules with very high speed will be very small
  2. BM2RT\frac{\mathrm{M}}{2 R T} in exponent implies that heavy molecules are unlikely to be found with very high speed
  3. Cv2\mathbf{v}^2 in pre-exponential term implies very slow molecules will be very small
  4. DM2RT\frac{\mathrm{M}}{2 \mathrm{RT}} in pre-exponential term implies that heavy molecules are unlikely to be found with very high speeds

Correct answer

D. M2RT\frac{\mathrm{M}}{2 \mathrm{RT}} in pre-exponential term implies that heavy molecules are unlikely to be found with very high speeds

Step-by-step solution

Remaining part of the function will make the overall fraction =1=1.
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