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JEE Main 20262 AprilMorning Shift
Exam
JEE Main
Year
2026
Date
2 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Practical Chemistry

JEE Main 2026 · 2 April · Morning Shift · Chemistry · Practical Chemistry

A salt with few drops of conc. HCl gives apple green colour in...

A salt with few drops of conc. HCl gives apple green colour in flame test. The group precipitate of the salt is dissolved in acetic acid and treated with K2CrO4K_2CrO_4 to give yellow precipitate. When the sodium carbonate extract of the salt solution is heated with conc. HNO3HNO_3 and ammonium molybdate, it resulted a canary yellow precipitate. The cation and anion present in the salt are respectively,

Options

  1. ACa2+Ca^{2+} and SO42−SO_4^{2-}
  2. BBa2+Ba^{2+} and PO43−PO_4^{3-}
  3. CMn2+Mn^{2+} and PO43−PO_4^{3-}
  4. DBa2+Ba^{2+} and SO42−SO_4^{2-}

Correct answer

B. Ba2+Ba^{2+} and PO43−PO_4^{3-}

Step-by-step solution

An apple green colour in the flame test indicates the presence of Ba2+Ba^{2+} ion.

The group precipitate of Ba2+Ba^{2+} is BaCO3BaCO_3, which dissolves in acetic acid to form barium acetate. Upon treatment with K2CrO4K_2CrO_4, it gives a yellow precipitate of barium chromate (BaCrO4BaCrO_4), confirming the presence of Ba2+Ba^{2+}.

When the sodium carbonate extract is heated with conc. HNO3HNO_3 and ammonium molybdate, the formation of a canary yellow precipitate indicates the presence of phosphate (PO43−PO_4^{3-}) ion. The canary yellow precipitate is ammonium phosphomolybdate, (NH4)3PO4⋅12MoO3(NH_4)_3PO_4 \cdot 12MoO_3.

Therefore, the cation is Ba2+Ba^{2+} and the anion is PO43−PO_4^{3-}.

Answer: Ba2+Ba^{2+} and PO43−PO_4^{3-}
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