A student has been given 0.314 g of an organic compound and asked to estimate Sulphur. During the experiment, the student has obtained 0.4813 g of barium sulphate. The percentage of sulphur present in the compound is $\_\_\_\_$ .
(Given Molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{~S}: 32, \mathrm{BaSO}_{4}: 233$ )

Question

A student has been given 0.314 g of an organic compound and asked to estimate Sulphur. During the experiment, the student has obtained 0.4813 g of barium sulphate. The percentage of sulphur present in the compound is

\_\_\_\_

.
(Given Molar mass in

\mathrm{g} \mathrm{mol}^{-1} \mathrm{~S}: 32, \mathrm{BaSO}_{4}: 233

)

Quantrex Academy · Accepted Answer

Correct answer: C. 21.05 %

Given: Mass of organic compound = 0.314 g, Mass of BaSO_4 obtained = 0.4813 g. \%S = (32)/(233) × (0.4813)/(0.314) × 100 = (32 × 0.4813 × 100)/(233 × 0.314) = (1540.16)/(73.162) = 21.05\%

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