0 . 01 MKMnO 4 solution was added to 20 . 0 mL of 0 . 05 M Mohr 's salt solution through a burette. The initial reading of 50 mL burette is zero. The volume of KMnO 4 solution left in the burette after the end point is....... mL . (near

Question

0 . 01 MKMnO 4 solution was added to 20 . 0 mL of 0 . 05 M Mohr 's salt solution through a burette. The initial reading of 50 mL burette is zero. The volume of KMnO 4 solution left in the burette after the end point is....... mL . (nearest integer)

Quantrex Academy · Accepted Answer

Correct answer: 0

Fe 2 + + MnO 4 - &#10230; Fe 3 + + Mn 2 + vf = 1 &#160;&#160; vf = 5 vf=Valency factor Milli equivalents of mohr's salt = milli equivalents of KMnO 4 1 &#215; 0 . 05 &#215; 20 = 5 0 . 01 &#215; V ml V ml =20ml Volume of KMnO 4 left = 50 - 20 = 30 ml

0 . 01 MKMnO 4 solution was added to 20 . 0 mL of 0 . 05 M Mohr 's salt solution through a burette. The initial reading of 50 mL burette is zero. The volume of KMnO 4 solution left in the burette after the end point is....... mL . (nearest integer)

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0 . 01 MKMnO 4 solution was added to 20 . 0 mL of 0 . 05 M Mohr &#39;s salt solution through a burette. The initial reading of 50 mL burette is zero. The volume of KMnO 4 solution left in the burette after the end point is....... mL . (nearest integer)

Correct answer

Step-by-step solution

More from Redox Reactions

0 . 01 MKMnO 4 solution was added to 20 . 0 mL of 0 . 05 M Mohr 's salt solution through a burette. The initial reading of 50 mL burette is zero. The volume of KMnO 4 solution left in the burette after the end point is....... mL . (nearest integer)