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What is the mass ratio of ethylene glycol ( C 2 H 6 O 2 , molar mass = 62 g / mol ) required for making 500 g of 0 . 25 molal aqueous solution and 250 mL of 0 . 25 molar aqueous solution?

Options

  1. A1 : 1
  2. B3 : 1
  3. C2 : 1
  4. D1 : 2

Correct answer

C. 2 : 1

Step-by-step solution

The molality of aqueous ethylene glycol solution = 0.25 m Mass of ethylene glycol required for 1000 g water = 62 4   =   15 . 5   gm Mass of solution = 1015.5 gm Mass of ethylene glycol in 500 gm solution =   15 . 5   ×   500 1015 . 5   =   7 . 63   gm Assuming density of solution as 1 gm/mL. Mass of ethylene glycol in 250 mL = 7 . 63 2   =   3 . 815   gm Mass ratio of ethylene glycol for making 500 gm of 0.25 m solution and 250 mL of 0.25 m solution

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