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JEE Main 202325 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
25 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2023 · 25 January · Evening Shift · Chemistry · Solutions

The number of pairs of the solution having the same value of the...

The number of pairs of the solution having the same value of the osmotic pressure from the following is
(Assume 100100 % ionization)

A. 0.500MC2H5OH(aq)0 . 500M{C}_{2}{H}_{5}OH ( aq ) and 0.25MKBr(aq)0 . 25MKBr ( aq )
B. 0.100MK4[Fe(CN)6](aq)0 . 100{M}_{}{K}_{4}\left[Fe ( CN{)}_{6}\right] ( aq ) and 0.100M0 . 100M FeSO4(NH4)2SO4(aq){FeSO}_{4}{\left({NH}_{4}\right)}_{2}{SO}_{4} ( aq )

C. 0.05MK4[Fe(CN)6]0 . 05M{K}_{4}\left[Fe ( CN{)}_{6}\right] (aq)and0.25MNaCland 0 . 25MNaCl (aq)( aq )
D. 0.15MNaCl(aq)0 . 15MNaCl ( aq ) and 0.1MBaCl2(aq)0 . 1M{BaCl}_{2} ( aq )
E. 0.02MKCl.MgCl2.6H2O(aq)0 . 02MKCl . {MgCl}_{2} . 6{H}_{2}O ( aq ) and 0.05M0 . 05M KCl(aq)KCl ( aq )

Correct answer

4

Step-by-step solution

We know,
π=iCRT\pi = iCRT

π∝iC\pi ∝ iC

A. 0.500MC2H5OH(aq)(iC=1×0.5=0.5)0 . 500M{C}_{2}{H}_{5}OH ( aq ) \left(iC = 1 \times 0 . 5 = 0 . 5\right) and 0.25MKBr(aq)(iC=2×0.25=0.5)0 . 25MKBr ( aq )\left(iC = 2 \times 0 . 25 = 0 . 5\right)


B. 0.100MK4[Fe(CN)6](aq)(iC=5×0.1=0.5)0 . 100{M}_{}{K}_{4}\left[Fe ( CN{)}_{6}\right] ( aq ) \left(iC = 5 \times 0 . 1 = 0 . 5\right) and 0 . 100M {FeSO}_{4}{\left({NH}_{4}\right)}_{2}{SO}_{4} ( aq )\left(iC = 5 \times 0 . 1 = 0 . 5\right)

C. 0.05MK4[Fe(CN)6](iC=5×0.05=0.25)0 . 05M{K}_{4}\left[Fe ( CN{)}_{6}\right]\left(iC = 5 \times 0 . 05 = 0 . 25\right) (aq)and0.25MNaCl(iC=2×0.25=0.5)(aq)and 0 . 25MNaCl\left(iC = 2 \times 0 . 25 = 0 . 5\right) ( aq )


D. 0.15MNaCl(aq)(iC=2×0.15=0.3)0 . 15MNaCl ( aq ) \left(iC = 2 \times 0 . 15 = 0 . 3\right) and 0 . 1M{BaCl}_{2} ( aq )\left(iC = 3 \times 0 . 1 = 0 . 3\right)


E. 0.02MKCl.MgCl2.6H2O(aq)(iC=5×0.02=0.1)0 . 02MKCl . {MgCl}_{2} . 6{H}_{2}O ( aq ) \left(iC = 5 \times 0 . 02 = 0 . 1\right) and 0 . 05M KCl ( aq )\left(iC = 2 \times 0 . 05 = 0 . 1\right)

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