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JEE Main 202325 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
25 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2023 · 25 January · Morning Shift · Chemistry · Solutions

The osmotic pressure of solutions of PVC in cyclohexanone at 300K...

The osmotic pressure of solutions of PVC in cyclohexanone at 300K300K are plotted on the graph. The molar mass of PVC is gmol−1g{mol}^{- 1} (Nearest integer)

The osmotic pressure of solutions of PVC in cyclohexanone at 300K are plotted on the graph. The molar mass of PVC is g

(Given : R=0.083LatmK−1mol−1R = 0 . 083Latm{K}^{- 1}{mol}^{- 1} )

Correct answer

0

Step-by-step solution

Using osmotic pressure in ideal gas equation:
π=M′RT=(W/MV)RT\pi = {M}^{'}RT = \left(\dfrac{W / M}{V}\right)RT

⇒π=(WV)(1M)RT=C(RTM)⇒ \pi = \left(\dfrac{W}{V}\right)\left(\dfrac{1}{M}\right)RT = C\left(\dfrac{RT}{M}\right)

⇒πC=RTM⇒ \dfrac{\pi}{C} = \dfrac{RT}{M}

If we assume given graph between πC\dfrac{\pi}{C} and CC

The osmotic pressure of solutions of PVC in cyclohexanone at 300K are plotted on the graph. The molar mass of PVC is g

Slope =RTM=0.083×300M=6×10−4= \dfrac{RT}{M} = \dfrac{0 . 083 \times 300}{M} = 6 \times {10}^{- 4}

∴M=0.083×3006×10−4=830×3006∴ M = \dfrac{0 . 083 \times 300}{6 \times {10}^{- 4}} = \dfrac{830 \times 300}{6}

=41,500gm/mole= 41, 500gm / mole

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