150 g of acetic acid was contaminated with 10 . 2 g ascorbic acid C 6 H 8 O 6 to lower down its freezing point by x × 10 - 1 ° C . The value of x is____ (Nearest integer). [Given K f = 3 . 9 K kg mol - 1 ; Molar mass of ascorbic acid = 176 g mol - 1 ]

Step-by-step solution

Given 150   g   of   solvent   CH 3 COOH And as solute 10 . 2   g ascorbic acid = 10 . 2 176   =   0 . 058 moles ΔT f = x × 10 - 1 ° C ΔT f = k f · molality = 3 . 9 × 0 . 058 150 × 1000 = 1 . 5   ° C = 15 × 10 - 1   ° C So, value of x=15.