When a certain amount of solid A is dissolved in 100   g of water at 25   ° C to make a dilute solution, the vapour pressure of the solution is reduced to one-half of that of pure water. The vapour pressure of pure water is 2

Question

When a certain amount of solid A is dissolved in 100 &#160; g of water at 25 &#160; &#176; C to make a dilute solution, the vapour pressure of the solution is reduced to one-half of that of pure water. The vapour pressure of pure water is 23 . 76 mmHg . The number of moles of solute A added is

Quantrex Academy · Accepted Answer

Correct answer: 5.55

We know that relative lowering in vapour pressure is given as P 0 - P S P o = solute n n Solute + solvent n P 0 - P S P S = solute n solvent n P 0 - P 0 2 P 0 2 = solute n solvent n solute n = solvent n = 100 18 = 5 . 55 &#160; mol

When a certain amount of solid A is dissolved in 100   g of water at 25   ° C to make a dilute solution, the vapour pressure of the solution is reduced to one-half of that of pure water. The vapour pressure of pure water is 23 . 76 mmHg . The number of moles of solute A added is

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When a certain amount of solid A is dissolved in 100 &#160; g of water at 25 &#160; &#176; C to make a dilute solution, the vapour pressure of the solution is reduced to one-half of that of pure water. The vapour pressure of pure water is 23 . 76 mmHg . The number of moles of solute A added is

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When a certain amount of solid A is dissolved in 100 g of water at 25 ° C to make a dilute solution, the vapour pressure of the solution is reduced to one-half of that of pure water. The vapour pressure of pure water is 23 . 76 mmHg . The number of moles of solute A added is