When a certain amount of solid A is dissolved in 100g of water at 25 ° C to make a dilute solution, the vapour pressure of the solution is reduced to one-half of that of pure water. The vapour pressure of pure water is

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Quantrex Academy · Accepted Answer

Correct answer: 5.55

We know that relative lowering in vapour pressure is given as
$\dfrac{{P}^{0} - {P}_{S}}{{P}^{o}} = \dfrac{solute n}{{n}_{Solute} + solvent n}$
$\dfrac{{P}^{0} - {P}_{S}}{{P}_{S}} = \dfrac{solute n}{solvent n}$
$\dfrac{{P}^{0} - \dfrac{{P}^{0}}{2}}{\dfrac{{P}^{0}}{2}} = \dfrac{solute n}{solvent n}$
$solute n = solvent n = \dfrac{100}{18} = 5 . 55mol$

When a certain amount of solid A is dissolved in 100g of water at...

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