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JEE Main 20266 AprilMorning Shift
Exam
JEE Main
Year
2026
Date
6 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2026 · 6 April · Morning Shift · Chemistry · Some Basic Concepts of Chemistry

An oxide of iron contains 69.9\% iron, its empirical formula, is:...

An oxide of iron contains 69.9%69.9\% iron, its empirical formula, is: (Given: Molar mass of Fe and O are 5656 and 1616 g mol−1^{-1} respectively.)

Options

  1. AFeO\text{FeO}
  2. BFe2O3\text{Fe}_2\text{O}_3
  3. CFe3O4\text{Fe}_3\text{O}_4
  4. DFeO3\text{FeO}_3

Correct answer

B. Fe2O3\text{Fe}_2\text{O}_3

Step-by-step solution

Mass percentage of Fe=69.9%\text{Fe} = 69.9\%

Mass percentage of O=100%−69.9%=30.1%\text{O} = 100\% - 69.9\% = 30.1\%

Number of moles of Fe=69.956=1.248\text{Fe} = \dfrac{69.9}{56} = 1.248

Number of moles of O=30.116=1.881\text{O} = \dfrac{30.1}{16} = 1.881

Molar ratio of Fe:O=1.248:1.881\text{Fe} : \text{O} = 1.248 : 1.881

Dividing by the smallest value, the ratio is 1.2481.248:1.8811.248=1:1.5\dfrac{1.248}{1.248} : \dfrac{1.881}{1.248} = 1 : 1.5

Multiplying by 22 to get the simplest whole number ratio, we get 2:32 : 3.

The empirical formula is Fe2O3\text{Fe}_2\text{O}_3.

Answer: Fe2O3\text{Fe}_2\text{O}_3
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