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JEE Main 20264 AprilEvening Shift
Exam
JEE Main
Year
2026
Date
4 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2026 · 4 April · Evening Shift · Chemistry · Some Basic Concepts of Chemistry

The correct order of total number of atoms present in (A) 2 moles...

The correct order of total number of atoms present in
(A) 22 moles of cyclohexane
(B) 684684 g of sucrose
(C) 90.890.8 L of dihydrogen at STP
is:

Options

  1. AC>A>BC>A>B
  2. BC>B>AC>B>A
  3. CB>C>AB>C>A
  4. DB>A>CB>A>C

Correct answer

D. B>A>CB>A>C

Step-by-step solution

For (A):

Formula of cyclohexane is C6H12C_6H_{12}.

Number of atoms per molecule = 6+12=186 + 12 = 18.

Total number of atoms in 22 moles = 2×18×NA=36NA2 \times 18 \times N_A = 36 N_A.

For (B):

Formula of sucrose is C12H22O11C_{12}H_{22}O_{11}.

Molar mass of sucrose = 342342 g/mol.

Number of moles = 684342=2\dfrac{684}{342} = 2 moles.

Number of atoms per molecule = 12+22+11=4512 + 22 + 11 = 45.

Total number of atoms = 2×45×NA=90NA2 \times 45 \times N_A = 90 N_A.

For (C):

Formula of dihydrogen is H2H_2.

Number of moles at STP = 90.822.7=4\dfrac{90.8}{22.7} = 4 moles.

Number of atoms per molecule = 22.

Total number of atoms = 4×2×NA=8NA4 \times 2 \times N_A = 8 N_A.

Comparing the total number of atoms:

90NA>36NA>8NA90 N_A > 36 N_A > 8 N_A

Therefore, the correct order is B>A>CB > A > C.

Answer: B>A>CB>A>C
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