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100 g of an ideal gas is kept in a cylinder of 416 L volume at 27 ° C under 1 . 5 bar pressure. The molar mass of the gas is g mol - 1 . (Nearest integer) (Given : R = 0 . 083 L bar K - 1 mol - 1 )

Correct answer

0

Step-by-step solution

PV = nRT 1 . 5 × 416 = 100 M . wt × 0 . 083 × 300 M.Wt. = 3 . 99 = 4   g / mole

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