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JEE Main20211 Sep 2021Evening ShiftChemistryStates of MatterActual

An empty LPG cylinder weighs 14 . 8 kg . When full, it weighs 29 . 0 kg and shows a pressure of 3 . 47 atm . In the course of use at ambient temperature, the mass of the cylinder is reduced to 23 . 0 kg . The final pressure inside the cylinder is _____ atm. (Nearest integer) (Assume LPG to be an ideal gas)

Correct answer

0

Step-by-step solution

Initial mass of gas = 29 - 14 . 8 = 14 . 2 Kg mass of gas used : = 29 - 23 = 6 Kg gas left = 14 . 2 - 6 = 8 . 2 Kg ( 1 )   3 . 47 × V = 14 . 2 × 10 3 M × R × T ( 2 )   p × V = 8 . 2 × 10 3 M × R × T Divide : ( 1 ) / ( 2 ) ⇒    3 . 47 P = 14 . 2 8 . 2 P = 2 . 003

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