Two flasks I and II shown below are connected by a valve of negligible volume. When the valve is opened, the final pressure of the system in bar is x × 10 - 2 . The value of x is (Integer answer) [Assume : Ideal gas; 1 bar = 10 5 Pa : Molar mass of N 2 = 28 . 0 mol - 1 ; R = 8 . 31 J mol - 1 K - 1

Step-by-step solution

Applying ; n - I + n - II initial = The final number of moles. n - I   and   n - II are the number of moles of gas in each container. ⇒ Assuming the system attains a final temperature of T (such that 300 < T < 60 ) ⇒ ∣ Heat lost by N 2 of container ( I ) | = | Heat gained by N 2 of container II | ⇒ n - I C m 300 - T ) = n - II C m ( T - 60 ) ⇒ 2 . 8 28 ( 300 - T ) = 0 . 2 28 (   T - 60 ) ⇒ 14 ( 300 - T ) = T - 60 ⇒ ( 14 × 300 + 60 ) 15 = T &#8658