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JEE Main202125 Jul 2021Evening ShiftChemistryStates of MatterActual

An LPG cylinder contains gas at a pressure of 300 kPa at 27 ° C . The cylinder can withstand the pressure of 1 . 2 × 10 6 Pa . The room in which the cylinder is kept catches fire. The minimum temperature at which the bursting of cylinder will take place is __________ C ∘ . (Nearest integer)

Correct answer

0

Step-by-step solution

P 1   T 1 = P 2   T 2 ⇒ 300 × 10 3 300 = 1 . 2 × 10 6   T 2 ⇒ T 2 = 1200   K T 2 = 927 ° C

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