The volume occupied by 4 . 75g of acetylene gas at 50 ° C and...

Given mass$= 4 . 75g ⇒ {C}_{2}{H}_{2}\left(g\right)$

$⇒$Moles$= \dfrac{4 . 75}{26}mol$

Temperature$= 50 + 273 = 323K$

$P = \dfrac{740}{760}atm$

$R = 0 . 0826\dfrac{ℓatm}{molK}$

$⇒ V = \dfrac{nRT}{P} = \dfrac{4 . 75}{26} \times \dfrac{0 . 0826 \times 323}{\left(\dfrac{740}{760}\right)}$

$⇒ V = \dfrac{96314 . 078}{19240} = 5 . 0059ℓ ≃ 5ℓ$