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JEE Main20206 Sep 2020Morning ShiftChemistryStates of MatterActual

A spherical balloon of radius 3   cm containing helium gas has a pressure of 48 × 10 - 3 bar. At the same temperature, the pressure, of a spherical balloon of radius 12   cm containing the same amount of gas will be … … … … . × 10 - 6 bar.

Correct answer

750

Step-by-step solution

if volume of 3 cm balloon is = V then volume of 12 cm radius balloon = 64 V So pressure will become 1   /   64 times = 1 / 64 × 48 × 10 - 3 bar = 750 × 10 - 3 bar

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