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JEE Main 20199 JanuaryMorning Shift
Exam
JEE Main
Year
2019
Date
9 January
Shift
Morning Shift
Subject
Chemistry
Chapter
States of Matter

JEE Main 2019 · 9 January · Morning Shift · Chemistry · States of Matter

0.5 moles of gas A and x moles of gas B exert a pressure of 200Pa...

0.50.5 moles of gas AA and xx moles of gas BB exert a pressure of 200Pa200Pa in a container of volume 10m310{m}^{3} at 1000K1000K . Given, RR is the gas constant in JK−1mol−1,x{JK}^{- 1}{mol}^{- 1}, x is:

Options

  1. A4+R2R\dfrac{4 + R}{2R}
  2. B2R4+R\dfrac{2R}{4 + R}
  3. C4−R2R\dfrac{4 - R}{2R}
  4. D2R4−R\dfrac{2R}{4 - R}

Correct answer

C. 4−R2R\dfrac{4 - R}{2R}

Step-by-step solution

According to the ideal gas equation:

PV=nRTPV = nRT

200×10=(0.5+x)R×1000200 \times 10 = ( 0 .5 + x ) R \times 1000

2=0.5R+xR2 = 0 .5 R + xR

x=2−0.5RR=4−R2Rx = \dfrac{2 - 0 .5 R}{R} = \dfrac{4 - R}{2R}
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