JEE Main2016ChemistryStates of MatterActual
Two closed bulbs of equal volume V containing an ideal gas initially at pressure p i and temperature T 1 are connected through a narrow tube of negligible volume, as shown in the figure below. The temperature of one of the bulbs is then raised to T 2 . The final pressure P f is:
Options
- A2 p i T 2 T 1 + T 2
- B2 p i T 1 T 2 T 1 + T 2
- Cp i T 1 T 2 T 1 + T 2
- D2 p i T 1 T 1 + T 2
Correct answer
A. 2 p i T 2 T 1 + T 2
Step-by-step solution
Given, two closed bulbs of equal volume V containing ideal gas initially of pressure p i     a n d   temperature T 1 , which are connected by a narrow tube of negligible volume. To find the final pressure P f , when one raised to T 2 : Number of moles of gas does not change, n T i = n T f P i V RT 1 + P i V RT 1 = P f V RT 1 + P f V RT 2 2 P i T 1 = P f T 1 + P f T 2  2 Pi T 1 =   P f ( T 1   +   T 2 ) T 1   ×   T 2 P f   =   2 P i   ( T 2 T 1