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JEE Main 20139 AprilOnline
Exam
JEE Main
Year
2013
Date
9 April
Mode
Online
Subject
Chemistry
Chapter
States of Matter

JEE Main 2013 · 9 April · Online · Chemistry · States of Matter

By how many folds the temperature of a gas would increase when the...

By how many folds the temperature of a gas would increase when the root mean square velocity of the gas molecules in a container of fixed volume is increased from 5×104 cm/s5 \times 10^4 \mathrm{~cm} / \mathrm{s} to 10×104 cm/s10 \times 10^4 \mathrm{~cm} / \mathrm{s} ?

Options

  1. ATwo
  2. BThree
  3. CSix
  4. DFour

Correct answer

D. Four

Step-by-step solution

r.m.s. velocity Vrms=3RTM\mathrm{V}_{\mathrm{rms}}=\sqrt{\frac{3 R T}{M}} i.e., V1 V2=T1 T2\frac{\mathrm{V}_1}{\mathrm{~V}_2}=\sqrt{\frac{\mathrm{T}_1}{\mathrm{~T}_2}} 5×10410×104=12=T1 T2\frac{5 \times 10^4}{10 \times 10^4}=\frac{1}{2}=\sqrt{\frac{\mathrm{T}_1}{\mathrm{~T}_2}} ∴T2=4T1\therefore \mathrm{T}_2=4 \mathrm{T}_1
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