Total number of ions from the following with noble gas configuration is
${Sr}^{2 +} ( Z = 38 ) , {Cs}^{+} ( Z = 55 ) , {La}^{2 +} ( Z = 57 ) {Pb}^{2 +}$ $( Z = 82 ) , {Yb}^{2 +} ( Z = 70 ) \text{and}{Fe}^{2 +} ( Z = 26 )$

Question

Total number of ions from the following with noble gas configuration is Sr ^ 2 + ( Z = 38 ) , Cs ^ + ( Z = 55 ) , La ^ 2 + ( Z = 57 ) Pb ^ 2 + ( Z = 82 ) , Yb ^ 2 + ( Z = 70 ) and Fe ^ 2 + ( Z = 26 )

Quantrex Academy · Accepted Answer

Correct answer: 2

Noble gas configuration = ns ^ 2 np ^ 6 [ _ 38 Sr ^ 2 + ] = [ _ 36 Kr ] [ Cs ^ + ] = [ _ 54 Xe ] [ Yb _ 70 ^ 2 + ] = [ _ 54 Xe ] 4 f ^ 14 [ _ 57 La ^ 2 + ] = [ _ 54 Xe ] 5 d ^ 1 [ _ 82 Pb ^ 2 + ] = [ _ 54 Xe ] 4 f ^ 14 5 d ^ 10 6 s ^ 2 [ _ 26 Fe ^ 2 + ] = [ _ 18 Ar ] 3 d ^ 6 Cs ^ + and Sr ^ 2 + have noble gas configuration, which are Xe and Kr , respectively. Hence, the answer is 2 .

Total number of ions from the following with noble gas...

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