The electronic configuration for Neodymium is: [Atomic Number for...

The atomic number of neodymium is $60$.

Therefore, the electronic configuration of neodymium (Nd) can be determined by distributing its electrons according to the Aufbau principle, Pauli exclusion principle, and Hund's rule.

Electronic configuration of $Nd ( Z = 60 )$ is;

$[ Xe ] 4{f}^{4}6{s}^{2}$

as the last electron of Neodymium enters the f subshell. so it is called a f-block element.

Hence option A is the answer.