JEE Main20236 Apr 2023Evening ShiftChemistryStructure of AtomActual
If the radius of the first orbit of hydrogen atom is a 0 , then de Broglie’s wavelength of electron in 3 rd orbit is
Options
- Aπ a 0 6
- Bπ a 0 3
- C6 π a 0
- D3 π a 0
Correct answer
C. 6 π a 0
Step-by-step solution
According to Bohr's angular momentum equation, m v r = n h 2 π The angular momentum equation for third orbit is m v r = 3 h 2 π 2 π r 3 = h m v According de Broglie's equation λ = h m v ∴   λ = 2 π 9 a 0 3 = 6 π a 0