JEE Main202229 Jul 2022Evening ShiftChemistryStructure of AtomActual
Given below are the quantum numbers for 4 electrons. A. n = 3 , l = 2 , m 1 = 1 , m s = + 1 2 B. n = 4 , l = 1 , m 1 = 0 , m s = + 1 2 C. n = 4 , l = 2 , m 1 = - 2 , m s = - 1 2 D. n = 3 , l = 1 , m 1 = - 1 , m s = + 1 2 The correct order of increasing energy is
Options
- AD < B < A < C
- BD < A < B < C
- CB < D < A < C
- DB < D < C < A
Correct answer
B. D < A < B < C
Step-by-step solution
Energy order of sub-shell decided by n + l value. Greater the n + l value of a sub-shell greater is its energy. If two sub-shells have same n + l values the orbital with greater principal quantum number has greater energy A ⇒ 3   d ⇒ n + l = 3 + 2 = 5 B ⇒ 4 p ⇒ n + l = 4 + 1 = 5 C ⇒ 4   d ⇒ n + l = 4 + 2 = 6 D ⇒ 3 s ⇒ n + l = 3 + 0 = 3 D < A < B < C