If the wavelength for an electron emitted from H - atom is 3 . 3 × 10 - 10 m , then energy absorbed by the electron in its ground state compared to minimum energy required for its escape from the atom, is____times. [Given : h = 6 . 626 × 10 - 34 Js , Mass of electron = 9 . 1 × 10 - 31 ]

Step-by-step solution

De Broglie's equation for calculating the wave length ( λ ) associated with the electron is given below λ = h p = h mV Let Kinetic energy of the particle of mass 'm' is K K = 1 2 mV 2 2 Km = m 2 V 2 2 Km = mV λ = h 2 mK h =Planck's constant= 6 . 62 × 10 - 27 erg - sec K = h 2 2   mλ 2 K = h 2 2   mλ 2 = 43 . 9 × 10 - 68 2 × 9 . 1 × 10 - 31 × 10 . 89 × 10 - 20 K = 2 . 215 × 10 - 18 E abs = E req + K E abs = Energy   absorbed E