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JEE Main202224 Jun 2022Evening ShiftChemistryStructure of AtomActual

The energy of one mole of photons of radiation of wavelength 300 nm is (Given : h = 6 . 63 × 10 - 34 J s , N A = 6 . 02 × 10 23 mol - 1 c = 3 × 10 8 m s - 1 )

Options

  1. A235   kJ   mol - 1
  2. B325   kJ   mol - 1
  3. C399   kJ   mol - 1
  4. D435   kJ   mol - 1

Correct answer

C. 399   kJ   mol - 1

Step-by-step solution

λ = 300 × 10 − 9 m Energy of single photon = hc λ Energy of N A photons = 6 .02 × 10 23 × 6 .63 × 10 − 34 × 3 × 10 8 300 × 10 − 9 =   3 . 99 × 10 5   J / mole = 399   KJ / mole

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