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JEE Main20198 Apr 2019Morning ShiftChemistryStructure of AtomActual

The quantum number of four electrons are given below: I . n = 4 , l = 2 , m l = – 2 , m s = – 1 / 2 I I . n = 3 , l = 2 , m l = 1 , m s = + 1 / 2 I I I . n = 4 , l = 1 , m l = 0 , m s = + 1 / 2 I V . n = 3 , l = 1 , m l = 1 , m s = – 1 / 2 The correct order of their increasing energies will be:

Options

  1. AI < I I I < I I < I V
  2. BI V < I I < I I I < I
  3. CI < I I < I I I < I I
  4. DI V < I I I < I I < I

Correct answer

B. I V < I I < I I I < I

Step-by-step solution

Higher the value of n + l higher will be energy. Hence, 3 p 4 < 3 d 5 < 4 p 5 < 4 d 7 If n + l same, then higher the value of, higher will be energy.

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