JEE Main 202622 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 22 January
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Thermodynamics (C)
JEE Main 2026 · 22 January · Morning Shift · Chemistry · Thermodynamics (C)
Match the List-I with List-II ( List-I (Thermodynamic Process)...
Match the List-I with List-II
(
)
Choose the correct answer from the options given below:
(
| List-I (Thermodynamic Process) | List-II | ||
| (Magnitude in kJ) | |||
| A. | Work done in reversible, isothermal expansion of 2 mol ideal gas from 2 dm^3 to 20 dm^3 at 300 K | I. | 4 |
| B. | Work done in irreversible isothermal expansion of 1 mol ideal gas from 1 m³ to 3 m³ at 300 K against constant pressure 3 kPa | II. | 11.5 |
| C. | Change in internal energy for adiabatic expansion of 1 mol ideal gas, T = 320 K, \overline{C}_V=R | III. | 6 |
| D. | Change in enthalpy at constant pressure of 1 mol ideal gas, T = 337 K, \overline{C}_p=R | IV. | 7 |
Choose the correct answer from the options given below:
Options
- AA-II, B-III, C-I, D-IV
- BA-III, B-II, C-IV, D-I
- CA-II, B-I, C-III, D-IV
- DA-I, B-II, C-III, D-IV
Correct answer
A. A-II, B-III, C-I, D-IV
Step-by-step solution
Calculate each thermodynamic quantity:
A. Reversible isothermal expansion (2 mol, 2→20 dm³, 300 K):
J ≈ 11.5 kJ → II
B. Irreversible isothermal expansion (1 mol, 1→3 m³, 3 kPa constant pressure):
J = 6 kJ → III
C. Adiabatic expansion (1 mol, = -320 K, ):
J ≈ 4 kJ → I
D. Enthalpy change (1 mol, = 337 K, ):
J ≈ 7 kJ → IV
Matching: A-II, B-III, C-I, D-IV
A. Reversible isothermal expansion (2 mol, 2→20 dm³, 300 K):
J ≈ 11.5 kJ → II
B. Irreversible isothermal expansion (1 mol, 1→3 m³, 3 kPa constant pressure):
J = 6 kJ → III
C. Adiabatic expansion (1 mol, = -320 K, ):
J ≈ 4 kJ → I
D. Enthalpy change (1 mol, = 337 K, ):
J ≈ 7 kJ → IV
Matching: A-II, B-III, C-I, D-IV