Let us consider a reversible reaction at temperature, T. In this reaction, both Δ H and Δ S were observed to have positive values. If the equilibrium temperature is Te , then the reaction becomes spontaneous at :

Correct answer: C. T Te For reaction to be spontaneous according to 2^ nd law: aligned & Δ G ( Δ H Δ S )=T_ e \& T > T_ e aligned

JEE Main 20254 AprilMorning Shift

JEE Main 2025 · 4 April · Morning Shift · Chemistry · Thermodynamics (C)

Let us consider a reversible reaction at temperature, T. In this...

Let us consider a reversible reaction at temperature, T.
In this reaction, both

\Delta \mathrm{H}

and

\Delta \mathrm{S}

were observed to have positive values. If the equilibrium temperature is Te , then the reaction becomes spontaneous at :

C. $\mathrm{T} \gt \mathrm{Te}$

For reaction to be spontaneous according to

2^{\text{nd }}

law:

\begin{aligned}& \Delta \mathrm{G} < 0 \& \Rightarrow \Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{ S} < 0 \& \Rightarrow \mathrm{ T} > \left(\frac{\Delta \mathrm{H}}{\Delta \mathrm{ S}}\right)=\mathrm{T}_{\mathrm{e}} \& \Rightarrow \mathrm{ T} > \mathrm{T}_{\mathrm{e}}\end{aligned}