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JEE Main 202522 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
22 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2025 · 22 January · Evening Shift · Chemistry · Thermodynamics (C)

Match List - I with List - II. Choose the correct answer from the...

Match List - I with List - II. Match List - I with List - II. Choose the correct answer from the options given below :
Choose the correct answer from the options given below :

Options

  1. A(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
  2. B(A)-(I), (B)-(II), (C)-(IV), (D)-(III)
  3. C(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  4. D(A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Correct answer

C. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)

Step-by-step solution

∵dH=dq (at P= constant) dH=CpdTdT(dHdT)P=CPdU=dq (at V= constant) dU=CVdT(dUdT)V=CV∵dG=VdP−SdT at P= constant, dP=0\begin{aligned} & \because \quad \mathrm{dH}=\mathrm{dq} \text{ (at } \mathrm{P}=\text{ constant) } \\ & \mathrm{dH}=\mathrm{CpdT}^{\mathrm{dT}} \\ & \left(\frac{\mathrm{dH}}{\mathrm{dT}}\right)_{\mathrm{P}}=\mathrm{C}_{\mathrm{P}} \\ & \mathrm{dU}=\mathrm{dq} \quad \text{ (at } \mathrm{V}=\text{ constant) } \\ & \mathrm{dU}=\mathrm{C}_{\mathrm{V}} \mathrm{dT} \\ & \left(\frac{\mathrm{dU}}{\mathrm{dT}}\right)_{\mathrm{V}}=\mathrm{C}_{\mathrm{V}} \\ & \because \mathrm{dG}=\mathrm{VdP}-\mathrm{SdT} \\ & \text{ at } \mathrm{P}=\text{ constant, } \mathrm{dP}=0\end{aligned} (dGdT)P=−S\left(\frac{d G}{d T}\right)_P=-S at T=\mathrm{T}= constant (dGdP)T=V\left(\frac{\mathrm{dG}}{\mathrm{dP}}\right)_{\mathrm{T}}=\mathrm{V}
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