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JEE Main 20245 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
5 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2024 · 5 April · Morning Shift · Chemistry · Thermodynamics (C)

The heat of combustion of solid benzoic acid at constant volume is...

The heat of combustion of solid benzoic acid at constant volume is (-321.30 \mathrm{~kJ}) at (27^{\circ} \mathrm{C}). The heat of combustion at constant pressure is ((-321.30-x \mathrm{R}) \mathrm{kJ}), the value of xx is _______.

Correct answer

0

Step-by-step solution

C6H5COOH(S)+152O2( g)→7CO2( g)+3H2O(ℓ)ΔH=ΔU+ΔngRT=−321.30−12R100×300=(−321.30−150R)kJ\begin{aligned} & \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}(\mathrm{S})+\frac{15}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow 7 \mathrm{CO}_2(\mathrm{~g})+3 \mathrm{H}_2 \mathrm{O}(\ell) \\ & \Delta \mathrm{H}=\Delta \mathrm{U}+\Delta \mathrm{n}_{\mathrm{g}} \mathrm{RT} \\ & =-321.30-\frac{1}{2} \frac{\mathrm{R}}{100} \times 300 \\ & =(-321.30-150 \mathrm{R}) \mathrm{kJ}\end{aligned}
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