Two reactions are given below: 2 Fe ( s ) + 3 2 O 2 ( g ) → Fe 2 O 3 ( s ) , Δ H o = - 822 kJ / mol C ( s ) + 1 2 O 2 ( g ) → CO ( g ) , Δ H o = - 110 kJ / mol Then enthalpy change for following reaction 3 C ( s ) + Fe 2 O 3 ( s ) → 2 Fe ( s ) + 3 CO ( g )

Step-by-step solution

Enthalpy change is the standard enthalpy of formation, in any general chemical reaction, the reactants undergo chemical changes and combine to give products. It can be represented by the following equation: Reactant → Product From the given equations, 2 Fe ( s ) + 3 2 O 2 ( g ) → Fe 2 O 3 ( s ) , Δ H o = - 822 kJ / mol .........(i) C ( s ) + 1 2 O 2 ( g ) → CO ( g ) , ΔH ° = - 110 kJ / mol ....(ii) 3 C ( s ) + Fe 2 O 3 ( s ) → 2 Fe ( s ) + 3 CO ( g ) , ΔH 3 = ? The value of ΔH 3 can be calculated as, ΔH 3 = 3 × ΔH