Enthalpies of formation of CCl 4 ( g ) , H 2 O ( g ) , CO 2 ( g ) and HCl are - 105 , - 242 , - 394 and - 92 kJ mol - 1 respectively. The magnitude of enthalpy of the reaction given below is kJmol - 1 . (nearest integer) CCl 4 ( g ) + 2 H 2

Question

Enthalpies of formation of CCl 4 ( g ) , H 2 O ( g ) , CO 2 ( g ) and HCl are - 105 , - 242 , - 394 and - 92 kJ mol - 1 respectively. The magnitude of enthalpy of the reaction given below is kJmol - 1 . (nearest integer) CCl 4 ( g ) + 2 H 2 O ( g ) &#8594; CO 2 ( g ) + 4 HCl ( g )

Quantrex Academy · Accepted Answer

Correct answer: 0

Using Hess's law of constant heat summation: Enthalpy of reaction = Enthalpy of formation of products - Enthalpy of formation of reactants &#8756; &#916;H f &#176; = &#916;H f &#176; CO 2 , &#160; g + 4 &#916;H f &#176; ( HCl ) - &#916;H f &#176; CCl 4 - 2 &#916;H f &#176; H 2 O , r = [ - 394 ] + 4 [ - 92 ] + 105 - 2 &#215; [ 242 ] = - 394 - 368 + 105 + 484 = - 173 &#160; kJ / mole

Enthalpies of formation of CCl 4 ( g ) , H 2 O ( g ) , CO 2 ( g ) and HCl are - 105 , - 242 , - 394 and - 92 kJ mol - 1 respectively. The magnitude of enthalpy of the reaction given below is kJmol - 1 . (nearest integer) CCl 4 ( g ) + 2 H 2 O ( g ) → CO 2 ( g ) + 4 HCl ( g )

Correct answer

Step-by-step solution

More from Thermodynamics (C)

Enthalpies of formation of CCl 4 ( g ) , H 2 O ( g ) , CO 2 ( g ) and HCl are - 105 , - 242 , - 394 and - 92 kJ mol - 1 respectively. The magnitude of enthalpy of the reaction given below is kJmol - 1 . (nearest integer) CCl 4 ( g ) + 2 H 2 O ( g ) &#8594; CO 2 ( g ) + 4 HCl ( g )

Correct answer

Step-by-step solution

More from Thermodynamics (C)

Enthalpies of formation of CCl 4 ( g ) , H 2 O ( g ) , CO 2 ( g ) and HCl are - 105 , - 242 , - 394 and - 92 kJ mol - 1 respectively. The magnitude of enthalpy of the reaction given below is kJmol - 1 . (nearest integer) CCl 4 ( g ) + 2 H 2 O ( g ) → CO 2 ( g ) + 4 HCl ( g )