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JEE Main 202330 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
30 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2023 · 30 January · Evening Shift · Chemistry · Thermodynamics (C)

1 mole of ideal gas is allowed to expand reversibly and...

11 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C27 ° C. The work done is 3kJmol−13kJ{mol}^{- 1}. The final temperature of the gas is _____ KK (Nearest integer). Given Cv=20Jmol−1K−1{C}_{v} = 20J{mol}^{- 1}{K}^{- 1}

Correct answer

0

Step-by-step solution

From first law of thermodynamics:
∆U=q+W∆ U = q + W
We know for adiabatic process,
∴q=0∴ q = 0

∴ΔU=w⇒m×Cv×∆T=w∴ \Delta U = w ⇒ m \times {C}_{v} \times ∆ T = w

⇒1×20×[T2−300]=−3000⇒ 1 \times 20 \times \left[{T}_{2} - 300\right] = - 3000

⇒T2−300=−150⇒ {T}_{2} - 300 = - 150

∴T2=150K∴ {T}_{2} = 150K

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