While performing a thermodynamics experiment, a student made the following observations, HCl + NaOH → NaCl + H 2 O Δ H = - 57 . 3   kJ   mol - 1 CH 3 COOH + NaOH → CH 3 COONa + H 2 O ΔH = - 55 . 3   kJ   mol - 1 . The enthalpy of ionization of CH 3 COOH as calculated by the student is kJ   mol - 1 .

Step-by-step solution

The enthalpy of neutralization (ΔH n ) is the change in enthalpy that occurs when one equivalent of an acid and a base undergo a neutralization reaction to form water and a salt. It is a special case of the enthalpy of reaction. It is defined as the energy released with the formation of 1 mole of water. △ H   Ionization   of   weak   acid   = ∆ H   Neutralization   of     W   A   +   S   B   −   ∆ H   Neutr