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The standard entropy change for the reaction 4 Fe s + 3 O 2 g → 2 Fe 2 O 3 s is - 550 J K - 1 at 298 K [Given : The standard enthalpy change for the reaction is - 165 kJ mol - 1 ]. The temperature in K at which the reaction attains equilibrium is (Nearest Integer)

Correct answer

0

Step-by-step solution

4 Fe s + 3 O 2 g → 3 Fe 2 O 3 s    ΔS r = - 550   J / K ΔS r = - 165   kJ / mole At equilibrium ΔG = 0 T = ΔH ΔS at equilibrium = - 165 × 10 3 - 550 = 300   K

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