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2 O 3 g ⇌ 3 O 2 g At 300 K , ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm pressure is - . . . . . . J mol - 1 . (Nearest integer) [Given: ln 1 . 35 = 0 . 3 and R = 8 . 3 J K - 1 mol - 1 ]

Correct answer

0

Step-by-step solution

2 O 3 g ⇌ 3 O 2 g Initially 1 mole 0 1 - 0 . 5 3 2 × 0 . 5 0 . 5 mole 1 . 5 2 = 0 . 75 mole K p = P O 2 3 P O 3 2 = 0 . 75 1 . 25 3 0 . 5 1 . 25 2 = 3 5 3 2 5 2 = 0 . 6 3 0 . 4 2 = 0 . 216 0 . 16 = 1 . 35 ΔG ° = - RTlnK p = - 8 . 3 × 300 ln 1 . 35 = - 8 . 3 × 300 × 0 . 3 = - 747 J / mole

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