2 O _ 3 (g) ⇌ 3 O _ 2 (g) At 300K , ozone is fifty percent...

2{O}_{3}\left(g\right) ⇌ 3{O}_{2}\left(g\right)$</p><p>Initially$1$mole$0$</p><p>\left(1 - 0 . 5\right)$\dfrac{3}{2} \times 0 . 5$</p><p>$0 . 5$mole$\dfrac{1 . 5}{2} = 0 . 75$mole</p><p>${K}_{p} = \dfrac{{\left({P}_{{O}_{2}}\right)}^{3}}{{\left({P}_{{O}_{3}}\right)}^{2}} = \dfrac{{\left(\dfrac{0 . 75}{1 . 25}\right)}^{3}}{{\left(\dfrac{0 . 5}{1 . 25}\right)}^{2}} = \dfrac{{\left(\dfrac{3}{5}\right)}^{3}}{{\left(\dfrac{2}{5}\right)}^{2}}$</p><p>$= \dfrac{{\left(0 . 6\right)}^{3}}{{\left(0 . 4\right)}^{2}} = \dfrac{\left(0 . 216\right)}{\left(0 . 16\right)} = 1 . 35$</p><p>$\Delta G ° = - {RTlnK}_{p}$</p><p>$= - 8 . 3 \times 300\ln 1 . 35$</p><p>$= - 8 . 3 \times 300 \times 0 . 3$</p><p>$= - 747J / mole