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JEE Main202125 Jul 2021Morning ShiftChemistryThermodynamics (C)Actual

At 298 . 2 K the relationship between enthalpy of bond dissociation (in kJ mol - 1 ) for hydrogen E H and its isotope, deuterium E D , is best described by:

Options

  1. AE H = 1 2 E D
  2. BE H = E D
  3. CE H = E D - 7 . 5
  4. DE H = 2 E D

Correct answer

C. E H = E D - 7 . 5

Step-by-step solution

Enthalpy of bond dissociation kJ / mole at 298 . 2   K For, hydrogen = 435 . 88 For, Deuterium = 443 . 35 ∴   E H ≃ E D - 7 . 5

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