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JEE Main 202122 JulyMorning Shift
Exam
JEE Main
Year
2021
Date
22 July
Shift
Morning Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2021 · 22 July · Morning Shift · Chemistry · Thermodynamics (C)

If the standard molar enthalpy change for combustion of graphite...

If the standard molar enthalpy change for combustion of graphite powder is −2.48×102kJmol−1- 2 . 48 \times {10}^{2}kJ{mol}^{- 1}, the amount of heat generated on combustion of 1g1g of graphite powder in kJkJ (Nearest integer):

Correct answer

0

Step-by-step solution

1mol1mol graphite =12gmC= 12gmC
Ans. =24812=20.67kJ/gm= \dfrac{248}{12} = 20 . 67kJ / gm heat evolved
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