The Gibbs energy change (in J ) for the given reaction at Cu 2 + = Sn 2 + = 1  M and 298 K is : Cu s + Sn 2 + aq . → Cu 2 + aq . + Sn s ; E Sn 2 + Sn 0 = − 0 .16   V ,   E Cu 2 + Cu 0 = 0 .34   V , Take F

Question

The Gibbs energy change (in J ) for the given reaction at Cu 2 + = Sn 2 + = 1 &#8201;M and 298 K is : Cu s + Sn 2 + aq . &#8594; Cu 2 + aq . + Sn s ; E Sn 2 + Sn 0 = &#8722; 0 .16 &#8201; V , &#8201; E Cu 2 + Cu 0 = 0 .34 &#8201; V , Take F = 96500 &#8201; C &#8201; mol &#8722; 1

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Correct answer: 96500

E cell&#160; 0 = E Sn 2 + / Sn 0 - E Cu 2 + / Cu 0 = - 0 . 16 - 0 . 34 = - 0 . 50 V &#916; G 0 = - nFE cell 0 = - 2 &#215; 96500 &#215; ( - 0 . 5 ) = 96500 &#160; J = 96 . 5 &#160; KJ = 96500 &#160; J

The Gibbs energy change (in J ) for the given reaction at Cu 2 + = Sn 2 + = 1  M and 298 K is : Cu s + Sn 2 + aq . → Cu 2 + aq . + Sn s ; E Sn 2 + Sn 0 = − 0 .16   V ,   E Cu 2 + Cu 0 = 0 .34   V , Take F = 96500   C   mol − 1

Correct answer

Step-by-step solution

More from Thermodynamics (C)

The Gibbs energy change (in J ) for the given reaction at Cu 2 + = Sn 2 + = 1 &#8201;M and 298 K is : Cu s + Sn 2 + aq . &#8594; Cu 2 + aq . + Sn s ; E Sn 2 + Sn 0 = &#8722; 0 .16 &#8201; V , &#8201; E Cu 2 + Cu 0 = 0 .34 &#8201; V , Take F = 96500 &#8201; C &#8201; mol &#8722; 1

Correct answer

Step-by-step solution

More from Thermodynamics (C)

The Gibbs energy change (in J ) for the given reaction at Cu 2 + = Sn 2 + = 1 M and 298 K is : Cu s + Sn 2 + aq . → Cu 2 + aq . + Sn s ; E Sn 2 + Sn 0 = − 0 .16 V , E Cu 2 + Cu 0 = 0 .34 V , Take F = 96500 C mol − 1