JEE Main201912 Apr 2019Evening ShiftChemistryThermodynamics (C)Actual

The incorrect match in the following is:

Options

AΔ G 0 < 0 , K > 1
BΔ G 0 > 0 , K < 1
CΔ G 0 = 0 , K = 1
DΔ G 0 < 0 , K < 1

Correct answer

D. Δ G 0 < 0 , K < 1

Step-by-step solution

We know that Δ G ° = - R T l n K Δ G ° = - 2.303   R T log ⁡ K so for k = 1 , log ⁡ K = 0 hence Δ G ° = 0   ; for k > 1 , log ⁡ K > 0   Δ G ° = - v e for k < 1 , log ⁡ K < 0 Δ G ° > 0

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