JEE Main201912 Apr 2019Morning ShiftChemistryThermodynamics (C)Actual
Enthalpy of sublimation of iodine is 24 c a l g - 1 at 200 ° C . If specific heat of I 2 (s) and I 2 (vap) are 0.055 and 0.031 c a l g - 1 K - 1 respectively, then enthalpy of sublimation of iodine at 250 ° C in c a l g - 1 is:
Options
- A11.4
- B2.85
- C22.8
- D5.7
Correct answer
C. 22.8
Step-by-step solution
I 2 s → I 2 g Δ H 250 o C - Δ H 200 o C = Δ C p m T 2 - T 1 Δ H 250 o C - 24 = 0.013 - 0.055 × 50 Δ H 250 o C - 24 = - 1.2 ( Δ H ) 250 o C = 22.8   J / g m