JEE Main201815 Apr 2018Evening ShiftChemistryThermodynamics (C)Actual
_ f G ^ at 500 ~K for substance ' S ' in liquid state and gaseous state are +100.7 kcal mol ⁻¹ and +103 kcal mol ⁻¹ , respectively. Vapour pressure of liquid ' S ' at 500 ~K is approximately equal to: ( R =2 cal K ⁻¹ ~mol ⁻¹ ) .
Options
- A100 ~atm
- B1 ~atm
- C10 ~atm
- D0.1 ~atm
Correct answer
C. 10 ~atm
Step-by-step solution
aligned & G _ rxn ^ o = _ f G ^ (vapour) - _ f G ^ (liquid) & G _ rxn ^ o =103-100.7=2.3 kcal / mol &=2300 cal / mol & G _ rxn ^ o =- RT K &2300 cal / mol =-2 cal / mol K 500 ~K K & K =2.3 & ~K =10 ~atm = Vapour pressure of liquid ' S ' aligned Vapour pressure of liquid ' S ' at 500 ~K is approximately equal to 10 ~atm .