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JEE Main201815 Apr 2018Evening ShiftChemistryThermodynamics (C)Actual

_ f G ^ at 500 ~K for substance ' S ' in liquid state and gaseous state are +100.7 kcal mol ⁻¹ and +103 kcal mol ⁻¹ , respectively. Vapour pressure of liquid ' S ' at 500 ~K is approximately equal to: ( R =2 cal K ⁻¹ ~mol ⁻¹ ) .

Options

  1. A100 ~atm
  2. B1 ~atm
  3. C10 ~atm
  4. D0.1 ~atm

Correct answer

C. 10 ~atm

Step-by-step solution

aligned & G _ rxn ^ o = _ f G ^ (vapour) - _ f G ^ (liquid) & G _ rxn ^ o =103-100.7=2.3 kcal / mol &=2300 cal / mol & G _ rxn ^ o =- RT K &2300 cal / mol =-2 cal / mol K 500 ~K K & K =2.3 & ~K =10 ~atm = Vapour pressure of liquid ' S ' aligned Vapour pressure of liquid ' S ' at 500 ~K is approximately equal to 10 ~atm .

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