JEE Main201815 Apr 2018Morning ShiftChemistryThermodynamics (C)Actual
An ideal gas undergoes a cyclic process as shown in Figure. aligned & U _ BC =-5 ~kJ ~mol ⁻¹, q _ AB =2 ~kJ ~mol ⁻¹ & ~W _ AB =-5 ~kJ ~mol ⁻¹, ~W _ CA =3 ~kJ ~mol ⁻¹ aligned Heat absorbed by the system during process CA is:
Options
- A-5 ~kJ ~mol ⁻¹
- B+5 ~kJ ~mol ⁻¹
- C18 ~kJ ~mol ⁻¹
- D-18 ~kJ ~mol ⁻¹
Correct answer
B. +5 ~kJ ~mol ⁻¹
Step-by-step solution
U _ AB = q _ AB + W _ AB =2+(-5)=-3 ~kJ / mol U _ BC =-5 ~kJ / mol For cyclic process, U =0 aligned & U _ AB + U _ BC + U _ CA =0 & U _ CA =- U _ AB - U _ BC & U _ CA =-(-3)-(-5)=8 ~kJ / mol & U _ CA = q _ CA + W _ CA &8= q _ CA +3 & q _ CA =+5 ~kJ / mol aligned Heat absorbed has positive sign.