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JEE Main2018ChemistryThermodynamics (C)Actual

An ideal gas undergoes a cyclic process as shown in the figure ∆ U BC = - 5 KJmol - 1 , q AB = 2 KJmol - 1 W AB = - 5 KJmol - 1 , W CA = 3 KJmol - 1 Heat absorbed by the system during process CA is

Options

  1. A- 5 KJmol - 1
  2. B+ 5 KJmol - 1
  3. C- 18 KJmol - 1
  4. D18 KJmol - 1

Correct answer

B. + 5 KJmol - 1

Step-by-step solution

AB → isobaric BC → isochoric CA → not defined For cyclic process, ΔU=0 ∆ U AB = q + W = 2 - 5 = - 3 ∆ U ABC = ∆ U AB + ∆ U BC = - 3 - 5 = - 8   KJ ∆ U CA = + 8 = Q +   W 8 = Q + 3 Q = + 5   kJ Therefore, the heat absorbed by the system during process CA is + 5   KJmol − 1 .

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